(7x+4)(2x^2-9x-5)=0

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Solution for (7x+4)(2x^2-9x-5)=0 equation: 


Simplifying
(7x + 4)(2x2 + -9x + -5) = 0

Reorder the terms:
(4 + 7x)(2x2 + -9x + -5) = 0

Reorder the terms:
(4 + 7x)(-5 + -9x + 2x2) = 0

Multiply (4 + 7x) * (-5 + -9x + 2x2)
(4(-5 + -9x + 2x2) + 7x * (-5 + -9x + 2x2)) = 0
((-5 * 4 + -9x * 4 + 2x2 * 4) + 7x * (-5 + -9x + 2x2)) = 0
((-20 + -36x + 8x2) + 7x * (-5 + -9x + 2x2)) = 0
(-20 + -36x + 8x2 + (-5 * 7x + -9x * 7x + 2x2 * 7x)) = 0
(-20 + -36x + 8x2 + (-35x + -63x2 + 14x3)) = 0

Reorder the terms:
(-20 + -36x + -35x + 8x2 + -63x2 + 14x3) = 0

Combine like terms: -36x + -35x = -71x
(-20 + -71x + 8x2 + -63x2 + 14x3) = 0

Combine like terms: 8x2 + -63x2 = -55x2
(-20 + -71x + -55x2 + 14x3) = 0

Solving
-20 + -71x + -55x2 + 14x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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